A.SoldierandBananas模拟[crayon-683cd7b74a58d160180578/]B.SoldierandBadges排序[crayon-683cd7b74a595725688618/]C.SoldierandCards暴力模拟个一百万次。。。[crayon-683cd7b74a59a958634649/]D.SoldierandNumberGame用筛法得出每个数质因子个数前缀和即可[crayon-683cd7b74a59d391735351/]E.SoldierandTraveling我比较愚蠢写了网络流。。正解是什么我不知道[crayon-683cd7b74a5a2207878670/] ...
1694.AnOldStoneGamef[x]表示x为根的树至少需要的石头,把子树按f排序后贪心即可[crayon-683cd7b74bc7f622715762/]poj1738.AnoldStoneGame参见discuss的神算法,据说是knuth提出的?[crayon-683cd7b74bc89901635099/]1737.ConnectedGraph跪大爷http://blog.csdn.net/PoPoQQQ/article/details/43525019[crayon-683cd7b74bc90576268561/]1742.Coins二进制拆分+bitset竟然过不了...我被题解骗了突然一想这不是以前做过...
A.AmrandMusic排序贪心[crayon-683cd7b74c267467802649/]B.AmrandPins算出距离除以直径[crayon-683cd7b74c271848822690/]C.GuessYourWayOut!按位考虑[crayon-683cd7b74c275137568940/]D.TheMathsLecture从后往前dpf(i,j,k)表示后i位,当前模为j,是否有后缀被K整除[crayon-683cd7b74c279990034249/]E.BreakingGood广搜,选可用边最多的路径[crayon-683cd7b74c27f031596637/] ...
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